16(t^2-12t+20)=0

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Solution for 16(t^2-12t+20)=0 equation:


Simplifying
16(t2 + -12t + 20) = 0

Reorder the terms:
16(20 + -12t + t2) = 0
(20 * 16 + -12t * 16 + t2 * 16) = 0
(320 + -192t + 16t2) = 0

Solving
320 + -192t + 16t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '16'.
16(20 + -12t + t2) = 0

Factor a trinomial.
16((2 + -1t)(10 + -1t)) = 0

Ignore the factor 16.

Subproblem 1

Set the factor '(2 + -1t)' equal to zero and attempt to solve: Simplifying 2 + -1t = 0 Solving 2 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1t = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1t = 0 + -2 -1t = 0 + -2 Combine like terms: 0 + -2 = -2 -1t = -2 Divide each side by '-1'. t = 2 Simplifying t = 2

Subproblem 2

Set the factor '(10 + -1t)' equal to zero and attempt to solve: Simplifying 10 + -1t = 0 Solving 10 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1t = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1t = 0 + -10 -1t = 0 + -10 Combine like terms: 0 + -10 = -10 -1t = -10 Divide each side by '-1'. t = 10 Simplifying t = 10

Solution

t = {2, 10}

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